(1-1/2)(1-1/2^2)(1-1/2^4)(1-1/2^8)+1/2^1要详细做法
发布网友
发布时间：2024-12-18 05:20
共1个回答
热心网友
时间：2025-01-16 20:59
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)/(1-1/2)+1/2^15
=(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^8)(1+1/2^8)*2+1/2^15
=(1-1/2^16)*2+1/2^15
=2-1/2^15+1/2^15
=2
热心网友
时间：2025-01-16 20:56
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)/(1-1/2)+1/2^15
=(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^8)(1+1/2^8)*2+1/2^15
=(1-1/2^16)*2+1/2^15
=2-1/2^15+1/2^15
=2
